<?xml version='1.0' encoding='UTF-8'?><?xml-stylesheet href="http://www.blogger.com/styles/atom.css" type="text/css"?><feed xmlns='http://www.w3.org/2005/Atom' xmlns:openSearch='http://a9.com/-/spec/opensearchrss/1.0/' xmlns:georss='http://www.georss.org/georss' xmlns:gd='http://schemas.google.com/g/2005' xmlns:thr='http://purl.org/syndication/thread/1.0'><id>tag:blogger.com,1999:blog-8327146876808784743</id><updated>2012-02-09T03:42:51.649-08:00</updated><title type='text'>SAT Math Tips</title><subtitle type='html'></subtitle><link rel='http://schemas.google.com/g/2005#feed' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/posts/default'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default?max-results=100'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/'/><link rel='hub' href='http://pubsubhubbub.appspot.com/'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><generator version='7.00' uri='http://www.blogger.com'>Blogger</generator><openSearch:totalResults>12</openSearch:totalResults><openSearch:startIndex>1</openSearch:startIndex><openSearch:itemsPerPage>100</openSearch:itemsPerPage><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-8239450822019247446</id><published>2012-02-02T19:52:00.000-08:00</published><updated>2012-02-02T19:52:20.548-08:00</updated><title type='text'>Moved</title><content type='html'>Hi all,&lt;br /&gt;&lt;br /&gt;I've moved this blog over to the more appropriately named:&lt;br /&gt;&lt;br /&gt;&lt;a href="http://satmath4life.blogspot.com/"&gt;http://satmath4life.blogspot.com/&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-8239450822019247446?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/8239450822019247446/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2012/02/moved.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/8239450822019247446'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/8239450822019247446'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2012/02/moved.html' title='Moved'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-128932983279997166</id><published>2012-01-21T17:07:00.000-08:00</published><updated>2012-01-29T00:54:09.757-08:00</updated><title type='text'>Electronic textbooks</title><content type='html'>&lt;div style="text-align: left;"&gt;&lt;span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"&gt;&lt;/span&gt;&lt;br /&gt;&lt;span style="font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"&gt;&lt;span style="color: #444444; line-height: 13px;"&gt;Lifetime membership for unlimited, legal downloads of electronic textbooks (over 3 million to choose from) for $49.95. Textbooks can be viewed on your computer, tablet, smartphone, e-Reader, etc.&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;div style="line-height: 13px;"&gt;&lt;span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;&lt;br /&gt;&lt;span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"&gt;&lt;span style="line-height: 14px;"&gt;&lt;a href="https://www.plimus.com/jsp/redirect.jsp?contractId=3099758&amp;amp;referrer=1033988"&gt;https://www.plimus.com/jsp/redirect.jsp?contractId=3099758&amp;amp;referrer=1033988&lt;/a&gt;&lt;/span&gt;&lt;/span&gt;&lt;br /&gt;&lt;div style="font-size: 10px; line-height: 14px;"&gt;&lt;span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"&gt;&lt;br /&gt;&lt;/span&gt;&lt;/div&gt;&lt;/div&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-128932983279997166?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/128932983279997166/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2012/01/lifetime-membership-for-unlimited-legal.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/128932983279997166'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/128932983279997166'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2012/01/lifetime-membership-for-unlimited-legal.html' title='Electronic textbooks'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-8309324502483657261</id><published>2012-01-20T04:08:00.000-08:00</published><updated>2012-02-02T19:48:02.595-08:00</updated><title type='text'>Long time, no post</title><content type='html'>Wow, I haven't made a post in over half a year. &amp;nbsp;I notice I have had around 1000 total page views, though. &amp;nbsp;It seems to be mostly from people doing a web search on various terms related to triangles. &amp;nbsp;I hope you all found that one post on finding the area of an isosceles triangle helpful. &lt;br /&gt;&lt;br /&gt;I'm sorry I haven't had the inclination to write more detailed posts. &amp;nbsp;I frequently get the urge to write things out, but never find the time to do so. &amp;nbsp;It would take enormous amounts of time to write out all the things I've ever wanted to flesh out in words.&lt;br /&gt;&lt;br /&gt;I am considering taking the time to write another detailed post. &amp;nbsp;Stay tuned.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-8309324502483657261?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/8309324502483657261/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2012/01/long-time-no-post.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/8309324502483657261'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/8309324502483657261'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2012/01/long-time-no-post.html' title='Long time, no post'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-4573671771774037385</id><published>2011-04-08T22:43:00.001-07:00</published><updated>2011-04-08T22:44:10.255-07:00</updated><title type='text'>College Confidential</title><content type='html'>Here's a great place to get information about the SAT, ACT, college admissions, and more:&lt;br /&gt;&lt;br /&gt;&lt;a href="http://talk.collegeconfidential.com/sat-act-tests-test-preparation/"&gt;http://talk.collegeconfidential.com/sat-act-tests-test-preparation/&lt;/a&gt;&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-4573671771774037385?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/4573671771774037385/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/04/college-confidential.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/4573671771774037385'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/4573671771774037385'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/04/college-confidential.html' title='College Confidential'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-2874025764204696263</id><published>2011-03-09T00:20:00.001-08:00</published><updated>2011-03-09T00:20:22.918-08:00</updated><title type='text'>Perfect square trivia</title><content type='html'>12^2 = 144&lt;br /&gt;21^2 = 441 &lt;br /&gt;&lt;br /&gt;13^2 = 169&lt;br /&gt;31^2 = 961&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-2874025764204696263?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/2874025764204696263/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/03/perfect-square-trivia.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/2874025764204696263'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/2874025764204696263'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/03/perfect-square-trivia.html' title='Perfect square trivia'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-2645245550002587832</id><published>2011-03-09T00:08:00.000-08:00</published><updated>2011-03-09T00:08:17.697-08:00</updated><title type='text'>Geometry Challenge</title><content type='html'>Take any parallelogram.&amp;nbsp; Construct squares on each side of the parallelogram.&amp;nbsp; Prove that the centers of the constructed squares form a square.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-2645245550002587832?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/2645245550002587832/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/03/geometry-challenge.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/2645245550002587832'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/2645245550002587832'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/03/geometry-challenge.html' title='Geometry Challenge'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-2857898878178951770</id><published>2011-03-08T23:27:00.000-08:00</published><updated>2011-03-08T23:27:15.490-08:00</updated><title type='text'>0.99999... = 1</title><content type='html'>Let x = 0.99999...&lt;br /&gt;&lt;br /&gt;10x = 9.99999...&lt;br /&gt;&lt;br /&gt;10x - x = 9.99999... - 9 = 9&lt;br /&gt;&lt;br /&gt;9x = 9&lt;br /&gt;&lt;br /&gt;x = 1&lt;br /&gt;&lt;br /&gt;Do you believe?&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-2857898878178951770?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/2857898878178951770/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/03/099999-1.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/2857898878178951770'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/2857898878178951770'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/03/099999-1.html' title='0.99999... = 1'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-3563678321814106501</id><published>2011-03-08T18:03:00.000-08:00</published><updated>2011-03-08T18:05:50.728-08:00</updated><title type='text'>Log problem</title><content type='html'>log 237.5812087593 = 2.375812087593 (approximately)&lt;br /&gt;&lt;br /&gt;What is the pattern here?&amp;nbsp; Can you write an equation for this that 2.375812087593 solves?&amp;nbsp; The equation has exactly one other solution.&amp;nbsp; What is the other solution?&amp;nbsp; Can you prove that these are the only two solutions?&lt;br /&gt;&lt;br /&gt;(This is beyond the scope of the SAT Reasoning Test, but is reasonably related to the SAT Math 2 subject test.)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-3563678321814106501?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/3563678321814106501/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/03/log-problem.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/3563678321814106501'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/3563678321814106501'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/03/log-problem.html' title='Log problem'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-932636879477979676</id><published>2011-03-08T17:59:00.000-08:00</published><updated>2011-03-08T17:59:17.242-08:00</updated><title type='text'>Digits Problem</title><content type='html'>Each letter represents a digit.&amp;nbsp; Solve for the digits and numbers.&lt;br /&gt;&lt;br /&gt;TWO + THREE + SEVEN = TWELVE&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-932636879477979676?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/932636879477979676/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/03/digits-problem.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/932636879477979676'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/932636879477979676'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/03/digits-problem.html' title='Digits Problem'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-448946792408419016</id><published>2011-02-12T19:44:00.000-08:00</published><updated>2011-02-12T21:13:20.408-08:00</updated><title type='text'>Perfect Squares</title><content type='html'>There's a certain amount of memorization that should be done for the math portion of the SAT.&amp;nbsp; Relying on just the formulas given on the test is not enough (those are just a small, incomplete subset of what you need to know, and you shouldn't need to refer to them while taking the test as you should have them memorized).&amp;nbsp; It's possible to get away with a lot using your calculator, but it's better not to.&lt;br /&gt;&lt;br /&gt;In school, you should have learned perfect squares up to at least 15^2 or 16^2.&amp;nbsp; These are also the ones you should know for the SAT.&amp;nbsp; The more you know, the better.&amp;nbsp; If you don't know these perfect squares now, take the time to memorize the ones you don't know so well.&amp;nbsp; (At the least, know how to generate a short list of them on your calculator very quickly--but memorization is the better choice.)&lt;br /&gt;&lt;br /&gt;Here's a list up to 20^2.&lt;br /&gt;&lt;br /&gt;1^2 = 1&lt;br /&gt;2^2 = 4&lt;br /&gt;3^2 = 9&lt;br /&gt;4^2 = 16&lt;br /&gt;5^2 = 25&lt;br /&gt;6^2 = 36&lt;br /&gt;7^2 = 49&lt;br /&gt;8^2 = 64&lt;br /&gt;9^2 = 81&lt;br /&gt;10^2 = 100&lt;br /&gt;&lt;br /&gt;11^2 = 121&lt;br /&gt;12^2 = 144&lt;br /&gt;13^2 = 169&lt;br /&gt;14^2 = 196&lt;br /&gt;15^2 = 225&lt;br /&gt;16^2 = 256&lt;br /&gt;17^2 = 289&lt;br /&gt;18^2 = 324&lt;br /&gt;19^2 = 361&lt;br /&gt;20^2 = 400&lt;br /&gt;&lt;br /&gt;There are many tricks and patterns with perfect squares, but I'll leave that for another time.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-448946792408419016?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/448946792408419016/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/02/perfect-squares.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/448946792408419016'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/448946792408419016'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/02/perfect-squares.html' title='Perfect Squares'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-156457617891932391</id><published>2011-02-08T00:16:00.000-08:00</published><updated>2011-02-08T02:26:13.757-08:00</updated><title type='text'>Isosceles Triangles - calculating area (given sides)</title><content type='html'>This is an essential skill for the SAT.&amp;nbsp; It is commonly needed  to directly solve a math problem on the SAT or as an important step in a  larger problem.&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;Definition:&lt;/b&gt;&lt;/u&gt;&amp;nbsp; Isosceles triangles are triangles that have at least 2 sides of equal length.&lt;br /&gt;&lt;br /&gt;There are many ways to find the area of various types of triangles.&amp;nbsp; In  this post, I will show you how to calculate the area of an isosceles  triangle given the lengths of the 3 sides.&amp;nbsp; The method illustrated is  relatively straight-forward and is used by many students.&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;Given:&lt;/b&gt;&lt;/u&gt; isosceles triangle with 3 given sides.&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;To find:&lt;/b&gt;&lt;/u&gt; area of triangle (height is by-product).&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;Method:&lt;/b&gt;&lt;/u&gt;&lt;br /&gt;&lt;br /&gt;1. Draw an altitude from the vertex between the 2 equal sides to the opposite side.&lt;br /&gt;&lt;br /&gt;This opposite side serves as the base corresponding to the altitude just drawn.&amp;nbsp; The base is now split in half.&amp;nbsp; The isosceles triangle is split into 2 congruent right triangles (can you prove this?).&lt;br /&gt;&lt;br /&gt;2. Next, find the length of this altitude using the Pythagorean theorem.&lt;br /&gt;&lt;br /&gt;3. Plug &amp;amp; chug into A = (1/2) b * h.&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;Example:&lt;/b&gt;&lt;/u&gt;&lt;br /&gt;&lt;br /&gt;A triangle is given with sides 5, 5, 8.&amp;nbsp; Choose the side of 8 to be the base.&amp;nbsp; Draw the altitude to this base.&amp;nbsp; Each of the right triangles formed has a hypotenuse of 5 and one leg of 4 (half of the side of 8).&amp;nbsp; The other leg is the same as the altitude of the original triangle.&amp;nbsp; It has length 3 by the Pythagorean theorem (3^2 + 4^2 = 5^2).&amp;nbsp; Thus, the original triangle has base 8, height 3, and area (1/2) * 8 * 3 = 12.&lt;br /&gt;&lt;br /&gt;&lt;div class="separator" style="clear: both; text-align: center;"&gt;&lt;a href="http://2.bp.blogspot.com/_PltDPkxQQ3A/TVEGQLoUGZI/AAAAAAAAAHA/e-gCvjtW-bI/s1600/isosceles+triangle.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"&gt;&lt;img border="0" height="132" src="http://2.bp.blogspot.com/_PltDPkxQQ3A/TVEGQLoUGZI/AAAAAAAAAHA/e-gCvjtW-bI/s400/isosceles+triangle.png" width="400" /&gt;&lt;/a&gt;&lt;/div&gt;&lt;br /&gt;&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;Note:&lt;/b&gt;&lt;/u&gt;&amp;nbsp; Equilateral triangles are isosceles.&amp;nbsp; You can find their areas in the same way.&amp;nbsp; The 2 right triangles you construct will be 30-60-90 triangles.&amp;nbsp; The height of the equilateral triangle will then be x * sqrt(3)/2, where x is the length of one of the sides.&amp;nbsp; The area of the equilateral triangle is then x^2 * sqrt(3) / 4.&amp;nbsp; These formulas for the height and area of an equilateral triangle are worth memorizing because equilateral triangles are so common on the SAT.&lt;br /&gt;&lt;br /&gt;&lt;u&gt;&lt;b&gt;Practice:&lt;/b&gt;&lt;/u&gt;&lt;br /&gt;&lt;br /&gt;1. Find the height and area of a triangle with sides 13, 13, 10.&amp;nbsp; (Area is 60.)&lt;br /&gt;&lt;br /&gt;2. Find the height and area of a triangle with sides 25, 25, 30.&amp;nbsp; (Area is 300.)&lt;br /&gt;&lt;br /&gt;3. Find the height and area of a triangle with sides 3, 3, 3.&amp;nbsp; (Area is 9 * sqrt(3) / 4.)&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-156457617891932391?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/156457617891932391/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/02/isosceles-triangles.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/156457617891932391'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/156457617891932391'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/02/isosceles-triangles.html' title='Isosceles Triangles - calculating area (given sides)'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><media:thumbnail xmlns:media='http://search.yahoo.com/mrss/' url='http://2.bp.blogspot.com/_PltDPkxQQ3A/TVEGQLoUGZI/AAAAAAAAAHA/e-gCvjtW-bI/s72-c/isosceles+triangle.png' height='72' width='72'/><thr:total>0</thr:total></entry><entry><id>tag:blogger.com,1999:blog-8327146876808784743.post-4492452977875340596</id><published>2011-02-07T23:54:00.000-08:00</published><updated>2012-01-29T00:58:57.334-08:00</updated><title type='text'>First post</title><content type='html'>Hi,&lt;br /&gt;&lt;br /&gt;I will use this blog for a variety of things.&amp;nbsp; Probably, mostly for SAT math tips, test-taking strategies, and study strategies for now...&lt;br /&gt;&lt;br /&gt;WARNING on math: I could get very technical about the way I write math, but I try not to in order to make things easier to understand.&amp;nbsp; For instance, I will write things like "triangle with sides 3, 4, 5" when I really mean the sides have lengths of 3, 4, and 5.&amp;nbsp; This is also the way I tend to speak in person.&lt;br /&gt;&lt;br /&gt;I'm not that careful about grammar, but feel free to correct me.&lt;br /&gt;&lt;br /&gt;I also tend to edit things a lot, so you might see things change after you read it the first time.&lt;br /&gt;&lt;br /&gt;Please feel free to ask questions or add other comments.&lt;div class="blogger-post-footer"&gt;&lt;img width='1' height='1' src='https://blogger.googleusercontent.com/tracker/8327146876808784743-4492452977875340596?l=mistersean.blogspot.com' alt='' /&gt;&lt;/div&gt;</content><link rel='replies' type='application/atom+xml' href='http://mistersean.blogspot.com/feeds/4492452977875340596/comments/default' title='Post Comments'/><link rel='replies' type='text/html' href='http://mistersean.blogspot.com/2011/02/first-post.html#comment-form' title='0 Comments'/><link rel='edit' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/4492452977875340596'/><link rel='self' type='application/atom+xml' href='http://www.blogger.com/feeds/8327146876808784743/posts/default/4492452977875340596'/><link rel='alternate' type='text/html' href='http://mistersean.blogspot.com/2011/02/first-post.html' title='First post'/><author><name>Sean</name><email>noreply@blogger.com</email><gd:image rel='http://schemas.google.com/g/2005#thumbnail' width='16' height='16' src='http://img2.blogblog.com/img/b16-rounded.gif'/></author><thr:total>0</thr:total></entry></feed>
