tag:blogger.com,1999:blog-83271468768087847432017-02-07T20:52:21.753-08:00SAT Math TipsSeanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.comBlogger12125tag:blogger.com,1999:blog-8327146876808784743.post-82394508220192474462012-02-02T19:52:00.000-08:002012-02-02T19:52:20.548-08:00MovedHi all,<br /><br />I've moved this blog over to the more appropriately named:<br /><br /><a href="http://satmath4life.blogspot.com/">http://satmath4life.blogspot.com/</a>Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-1289329832799971662012-01-21T17:07:00.000-08:002012-01-29T00:54:09.757-08:00Electronic textbooks<div style="text-align: left;"><span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"></span><br /><span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"></span><br /><span style="font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"><span style="color: #444444; line-height: 13px;">Lifetime membership for unlimited, legal downloads of electronic textbooks (over 3 million to choose from) for $49.95. Textbooks can be viewed on your computer, tablet, smartphone, e-Reader, etc.</span></span><br /><div style="line-height: 13px;"><span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"><br /></span></div><br /><span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"><span style="line-height: 14px;"><a href="https://www.plimus.com/jsp/redirect.jsp?contractId=3099758&referrer=1033988">https://www.plimus.com/jsp/redirect.jsp?contractId=3099758&referrer=1033988</a></span></span><br /><div style="font-size: 10px; line-height: 14px;"><span style="color: #333333; font-family: 'lucida grande', tahoma, verdana, arial, sans-serif;"><br /></span></div></div>Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-83093245024836572612012-01-20T04:08:00.000-08:002012-02-02T19:48:02.595-08:00Long time, no postWow, I haven't made a post in over half a year. I notice I have had around 1000 total page views, though. It seems to be mostly from people doing a web search on various terms related to triangles. I hope you all found that one post on finding the area of an isosceles triangle helpful. <br /><br />I'm sorry I haven't had the inclination to write more detailed posts. I frequently get the urge to write things out, but never find the time to do so. It would take enormous amounts of time to write out all the things I've ever wanted to flesh out in words.<br /><br />I am considering taking the time to write another detailed post. Stay tuned.Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-45736717717740373852011-04-08T22:43:00.001-07:002011-04-08T22:44:10.255-07:00College ConfidentialHere's a great place to get information about the SAT, ACT, college admissions, and more:<br /><br /><a href="http://talk.collegeconfidential.com/sat-act-tests-test-preparation/">http://talk.collegeconfidential.com/sat-act-tests-test-preparation/</a>Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-28740257642046962632011-03-09T00:20:00.001-08:002011-03-09T00:20:22.918-08:00Perfect square trivia12^2 = 144<br />21^2 = 441 <br /><br />13^2 = 169<br />31^2 = 961Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-26452455500025878322011-03-09T00:08:00.000-08:002011-03-09T00:08:17.697-08:00Geometry ChallengeTake any parallelogram. Construct squares on each side of the parallelogram. Prove that the centers of the constructed squares form a square.Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-28578988781789517702011-03-08T23:27:00.000-08:002011-03-08T23:27:15.490-08:000.99999... = 1Let x = 0.99999...<br /><br />10x = 9.99999...<br /><br />10x - x = 9.99999... - 9 = 9<br /><br />9x = 9<br /><br />x = 1<br /><br />Do you believe?Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-35636783218141065012011-03-08T18:03:00.000-08:002011-03-08T18:05:50.728-08:00Log problemlog 237.5812087593 = 2.375812087593 (approximately)<br /><br />What is the pattern here? Can you write an equation for this that 2.375812087593 solves? The equation has exactly one other solution. What is the other solution? Can you prove that these are the only two solutions?<br /><br />(This is beyond the scope of the SAT Reasoning Test, but is reasonably related to the SAT Math 2 subject test.)Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-9326368794779796762011-03-08T17:59:00.000-08:002011-03-08T17:59:17.242-08:00Digits ProblemEach letter represents a digit. Solve for the digits and numbers.<br /><br />TWO + THREE + SEVEN = TWELVESeanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-4489467924084190162011-02-12T19:44:00.000-08:002011-02-12T21:13:20.408-08:00Perfect SquaresThere's a certain amount of memorization that should be done for the math portion of the SAT. Relying on just the formulas given on the test is not enough (those are just a small, incomplete subset of what you need to know, and you shouldn't need to refer to them while taking the test as you should have them memorized). It's possible to get away with a lot using your calculator, but it's better not to.<br /><br />In school, you should have learned perfect squares up to at least 15^2 or 16^2. These are also the ones you should know for the SAT. The more you know, the better. If you don't know these perfect squares now, take the time to memorize the ones you don't know so well. (At the least, know how to generate a short list of them on your calculator very quickly--but memorization is the better choice.)<br /><br />Here's a list up to 20^2.<br /><br />1^2 = 1<br />2^2 = 4<br />3^2 = 9<br />4^2 = 16<br />5^2 = 25<br />6^2 = 36<br />7^2 = 49<br />8^2 = 64<br />9^2 = 81<br />10^2 = 100<br /><br />11^2 = 121<br />12^2 = 144<br />13^2 = 169<br />14^2 = 196<br />15^2 = 225<br />16^2 = 256<br />17^2 = 289<br />18^2 = 324<br />19^2 = 361<br />20^2 = 400<br /><br />There are many tricks and patterns with perfect squares, but I'll leave that for another time.Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-1564576178919323912011-02-08T00:16:00.000-08:002011-02-08T02:26:13.757-08:00Isosceles Triangles - calculating area (given sides)This is an essential skill for the SAT. It is commonly needed to directly solve a math problem on the SAT or as an important step in a larger problem.<br /><br /><u><b>Definition:</b></u> Isosceles triangles are triangles that have at least 2 sides of equal length.<br /><br />There are many ways to find the area of various types of triangles. In this post, I will show you how to calculate the area of an isosceles triangle given the lengths of the 3 sides. The method illustrated is relatively straight-forward and is used by many students.<br /><br /><u><b>Given:</b></u> isosceles triangle with 3 given sides.<br /><br /><u><b>To find:</b></u> area of triangle (height is by-product).<br /><br /><u><b>Method:</b></u><br /><br />1. Draw an altitude from the vertex between the 2 equal sides to the opposite side.<br /><br />This opposite side serves as the base corresponding to the altitude just drawn. The base is now split in half. The isosceles triangle is split into 2 congruent right triangles (can you prove this?).<br /><br />2. Next, find the length of this altitude using the Pythagorean theorem.<br /><br />3. Plug & chug into A = (1/2) b * h.<br /><br /><u><b>Example:</b></u><br /><br />A triangle is given with sides 5, 5, 8. Choose the side of 8 to be the base. Draw the altitude to this base. Each of the right triangles formed has a hypotenuse of 5 and one leg of 4 (half of the side of 8). The other leg is the same as the altitude of the original triangle. It has length 3 by the Pythagorean theorem (3^2 + 4^2 = 5^2). Thus, the original triangle has base 8, height 3, and area (1/2) * 8 * 3 = 12.<br /><br /><div class="separator" style="clear: both; text-align: center;"><a href="http://2.bp.blogspot.com/_PltDPkxQQ3A/TVEGQLoUGZI/AAAAAAAAAHA/e-gCvjtW-bI/s1600/isosceles+triangle.png" imageanchor="1" style="margin-left: 1em; margin-right: 1em;"><img border="0" height="132" src="http://2.bp.blogspot.com/_PltDPkxQQ3A/TVEGQLoUGZI/AAAAAAAAAHA/e-gCvjtW-bI/s400/isosceles+triangle.png" width="400" /></a></div><br /><br /><br /><u><b>Note:</b></u> Equilateral triangles are isosceles. You can find their areas in the same way. The 2 right triangles you construct will be 30-60-90 triangles. The height of the equilateral triangle will then be x * sqrt(3)/2, where x is the length of one of the sides. The area of the equilateral triangle is then x^2 * sqrt(3) / 4. These formulas for the height and area of an equilateral triangle are worth memorizing because equilateral triangles are so common on the SAT.<br /><br /><u><b>Practice:</b></u><br /><br />1. Find the height and area of a triangle with sides 13, 13, 10. (Area is 60.)<br /><br />2. Find the height and area of a triangle with sides 25, 25, 30. (Area is 300.)<br /><br />3. Find the height and area of a triangle with sides 3, 3, 3. (Area is 9 * sqrt(3) / 4.)Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0tag:blogger.com,1999:blog-8327146876808784743.post-44924529778753405962011-02-07T23:54:00.000-08:002012-01-29T00:58:57.334-08:00First postHi,<br /><br />I will use this blog for a variety of things. Probably, mostly for SAT math tips, test-taking strategies, and study strategies for now...<br /><br />WARNING on math: I could get very technical about the way I write math, but I try not to in order to make things easier to understand. For instance, I will write things like "triangle with sides 3, 4, 5" when I really mean the sides have lengths of 3, 4, and 5. This is also the way I tend to speak in person.<br /><br />I'm not that careful about grammar, but feel free to correct me.<br /><br />I also tend to edit things a lot, so you might see things change after you read it the first time.<br /><br />Please feel free to ask questions or add other comments.Seanhttp://www.blogger.com/profile/05749984493242487817noreply@blogger.com0